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1.5x^2-1=0
a = 1.5; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·1.5·(-1)
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6}}{2*1.5}=\frac{0-\sqrt{6}}{3} =-\frac{\sqrt{}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6}}{2*1.5}=\frac{0+\sqrt{6}}{3} =\frac{\sqrt{}}{3} $
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